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Simple Command Eddy Current Brake

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(@totally_dyno_beginner)
Posts: 12
Member
Topic starter
 

Hello guys,

Im currently working on a dyno project. The thing is I am an absloute beginner and I would like to request your skills and experience.

 

My goal is very simple : I want to reproduce the road steepness onto a roller test bench.

Since I know the testing vehicule's weight, I computed the required torque that I have to apply to brake (and then simulate the slope).

I dont need to chart any curve, nor load cell or software. 

 

To do so, I selected a Telma retarder (10 coil in series, 192V and 33.7A) and I designed a suitable chassis for it.

Now, I have to decide how am I going to supply and command the brake :

Knowing that the eddy current are made by electromagnets, I should be able to vary the braking force by adjusting the current intensity right ?

I found out a formula that describes the electromagnet behaviour H = I.N/L = I/perimeter where H strength of magnetic field, I current intensity, N number of turn of the coil, L length of the coil.

Thus, a simple power supplier with a current intensity adjusting potentiomete would be suitable for my need ?

 

Once again, my objective is very simple I am just too novice to know what is possible and how to do it.

 

I do thank you guys for your help,

Regards.

 
Posted : 03/08/2020 2:59 pm
(@admin)
Posts: 1457
Member Admin
 

Hi there,

You need a 0-192V DC power supply. There are a few options on the YourDyno wiki, just search for Eddy brake power supply.

The Telmas are typically 8 or 16 coils, giving either 96V or 192V, but yours may be different?

You don't need to worry about strengths of magnetic fields, etc, just control it with the voltage. The currents and magnetic fields will follow the voltage. 

Cheers,

 
Posted : 03/08/2020 10:01 pm
(@totally_dyno_beginner)
Posts: 12
Member
Topic starter
 

Thank you for your quick response. 

Yes, I am looking for a 0-192V DC power supply. In my case, the power supply has to ensure at least 192*33.7=6.34kW of power right ?

I guess the retarder I chose is a bit different, its reference is AF83-10. I selected it directly from the Telma website.

Thus, the increasing in voltage is going to produce a higher braking torque. Do you know how could I link these two values.

I mean as a matter of example, if I would like to produce 500Nm of braking torque what would be the voltage needed ?

 

Thank you again for your very helpful response.

Regard.

 

 
Posted : 04/08/2020 8:56 am
(@admin)
Posts: 1457
Member Admin
 

Your power calculation is mathematically correct, but are you sure it uses 33.7A at 192V? This is very high, most draw less than 25A at 192V. I did not find any specs for it, so maybe you are right.

JDM Dyno sells power supplies rated for 40A, you can check with him for an off the shelf solution (links in the wiki).

You cannot know what current gives 500Nm. It will vary with RPM and also temperature. So you need some type of feedback.

 
Posted : 04/08/2020 9:33 pm
(@totally_dyno_beginner)
Posts: 12
Member
Topic starter
 

Yes I am sure of the 33.7A. I will try tomorrow to post the electrical requirements sent by Telma in order to show you.

I am going to take a look at the JDM Dyno product.

It's embarassing, I thought there was an easy relation between the voltage/intensity and braking torque.

For instance, to perform a test, the basic procedure would be to start from 0V and go through the full range of voltage until 192V ? And I guess the maximum braking effect would be obtained at the maximum voltage ? Is that right ?

 
Posted : 04/08/2020 10:30 pm
(@totally_dyno_beginner)
Posts: 12
Member
Topic starter
 

This is an extract of the electrical specifications that Telma sent me 

 
Posted : 05/08/2020 9:53 am
(@admin)
Posts: 1457
Member Admin
 

OK, that was a clear spec, so correct then!

To do a controlled sweep you need a controller with a regulator, typically a PID regulator, that uses RPM as input and Brake control voltage as output. You can do this with YourDyno :-). 

It will typically not be 0-192V because most of the time you don't need to use the full power of the brake. Also the brake has a torque curve vs RPM, so you need some active regulator to get a smooth sweep. 

If your setup has enough Moment of inertia, then you can use a fixed voltage and still get a sweep. You need to chose a voltage that gives a lower torque than the engine has at each RPM. The engine will then sweep through the RPM range, and the sweep rate will change along the sweep, set by brake torque curve (for the chosen voltage ), the engine torque curve, and the moment of inertia. Possible... You still need a DAQ to read the RPM and load and power from the acceleration and MOI. A YourDyno controller is low cost in comparison to the rest of the system, so well worth it :-)! 

 

 
Posted : 05/08/2020 4:47 pm
(@mach_1)
Posts: 350
Member
 

Hi Totally_Dyno_Beginner , welcome to the forum

You realise you will not be applying full voltage to totally stop the engine totally ! By the way what engines are you planning on testing?

 

My goal is very simple : I want to reproduce the road steepness onto a roller test bench.

Since I know the testing vehicule's weight, I computed the required torque that I have to apply to brake (and then simulate the slope).

I dont need to chart any curve, nor load cell or software. 

Flat surface coasting down a freeway at 100km/h with no head wind a fairly aerodynamic little 1100kilogram weight vehicle in 5th gear overdrive engine revving at say between 1800 to 2100rpm  how much kilowatts ( throttle % opening ) will the engine have produce to maintain  a constant steady speed of 100km/hroughly ? ( lets ignore other variables factirs into the equation)

Now increase the surface incline from zero degrees to 45 degrees ( steepness) and repeat  the 100km/h speed process again ? Is that what I'm understanding you just want to do ??? Only going via one of you stated comments at the very 1st post ?

With a load cell and speed sensor at your finger tips you won't have to " computed the required torque "  as you can see it on a computer screen with the aid of your dyno  , i won't go into any further explanation. 

Just use a car differential to do the
ratio speed multiplication required

SStill don't know if you're building
a chassis dyno , engine dyno ,
"roller test bench" benchtop lab dyno ?

Just buy yourdyno blue box controller as admin suggest you wont go wrong and get Semikron SKPC 200 phase angle controller

https://yourdyno.com/YourDynoHelp/eddy-current-brake-control/

This post was modified 4 years ago by Mach_1
 
Posted : 06/08/2020 5:51 am
(@mach_1)
Posts: 350
Member
 

Disregard  the part " Just use a car differential to do the ratio speed multiplication required" sorry  think elsewhere  post!

 

 

 
Posted : 06/08/2020 7:28 am
(@totally_dyno_beginner)
Posts: 12
Member
Topic starter
 
Posted by: @mach_1

You realise you will not be applying full voltage to totally stop the engine totally ! By the way what engines are you planning on testing?

Flat surface coasting down a freeway at 100km/h with no head wind a fairly aerodynamic little 1100kilogram weight vehicle in 5th gear overdrive engine revving at say between 1800 to 2100rpm  how much kilowatts ( throttle % opening ) will the engine have produce to maintain  a constant steady speed of 100km/hroughly ? ( lets ignore other variables factirs into the equation)

SStill don't know if you're building
a chassis dyno , engine dyno ,
"roller test bench" benchtop lab dyno ?

I am building a roller test bench in order to test several railway vehicules. They are heavier and go slower than your example. The maximum weight is around 5000kg and the max speed is 35km/h. They are equipped with hydraulic engines.

I would like to show you pictures but I can not say much about it unfortunatly due to confidentiality. 

 

Your description is almost right : I want to know if the vehicule is able to go through a 2 degree slope while maintaining its constant speed (30km/h).

To do so, the engines have to create more torque to overcome the slope. And, I wanted the Telma braking torque play the role of the torque generated by the slope. 

I previously calculated the torque generated by the slope for each vehicule, that is the reason why I wanted to link voltage and braking torque (e.g. To create a 500 Nm braking torque, I have to adjust a certain value of voltage on the power supplier). Admin told me that is was better to perform a sweep test.

Thanks for your help, I know my project is a bit singular compared to what you are used to. 😓 

Cheers,

 
Posted : 06/08/2020 9:08 am
(@mach_1)
Posts: 350
Member
 

Ok gotcha  now if i understood you right , you want to stimulate tests without actaully putting the train cart on  the dyno?

 
Posted : 06/08/2020 9:49 am
(@mach_1)
Posts: 350
Member
 

simulated ooops not stimulate! Sorry

 
Posted : 06/08/2020 12:04 pm
(@totally_dyno_beginner)
Posts: 12
Member
Topic starter
 

I do want to put the train cart on the dyno otherwise I can not test anything.

The roller test bench allows be to test a rail vehicule without testing it on real railway. 

Sorry for my lack of clarity, I feel like I confused you.

 
Posted : 06/08/2020 12:41 pm
(@mach_1)
Posts: 350
Member
 

Are these train carts wheels steel ? Steel on rail track steel ? ( steel driven on steel surface )

 
Posted : 06/08/2020 7:02 pm
(@totally_dyno_beginner)
Posts: 12
Member
Topic starter
 

Yes, train carts wheels are galvanised steel and painted.

The rollers are pure steel (no treatment added on the surface).

 
Posted : 06/08/2020 9:06 pm
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