Q&A Forum

Notifications
Clear all

Load sensor output

4 Posts
2 Users
0 Reactions
4,416 Views
(@duzallcnc)
Posts: 7
Member
Topic starter
 

Hi,

   I have a land and sea engine dyno with their old style load sensor. I see that they have 

switched to the S type sensor that you are using. I would like to run your data acquisition 

in tandem with the land and sea dynomax software. I have the earliest version. At this point 

they don't acknowledge that I exist. (It was the greatest thing since sliced bread when I bought it)

Their rep told me to throw everything but the absorber in the trash and he could fix me up with a

basic unit for around 6k.  The software does have some features that yours doesn't have yet, which

is why I want to run them together. So finally my question is what is the output of your load sensor

0 - 5v ?  

Thanks

Andrew

 
Posted : 01/11/2016 9:01 pm
(@admin)
Posts: 1457
Member Admin
 

Hello, and thanks for your interest in YourDyno.

Yes, the load cell is driven by 5V. What will work is to let YourDyno read the load cell (old or new) and RPM (with its RPM sensor) and let Land&Sea read whatever other sensors they have there. You cannot share the load cell between two systems though, it needs to be driven by the same system as reads it, otherwise it will not be accurate. 

Does this answer your question? I am not sure I understood exactly what you wanted to do. 

Regards,
Jostein

 
Posted : 01/11/2016 9:17 pm
(@duzallcnc)
Posts: 7
Member
Topic starter
 

Yes that answers my question. I do want to feed the signal to both systems. I don't know if a pic chip as a buffer could accomplish the task ?  I haven't had time to research whether the Land and sea outputs 0 - 5 or millivolts.

 
Posted : 02/11/2016 4:57 pm
(@admin)
Posts: 1457
Member Admin
 

Hi, 

The best may be to just use 2 load cells in series!

A buffer or something like that is not a good option. You need a so-called ratiometric reading of the sensor. That means if you feed the load cell with not exactly 5V, but for example 4.9V, your reading will be off by a scale of 0.02 (1 - 4.9/5). If your voltage reference is driven by the same 5V signal (which is now 4.9V), the error will cancel, and you will read perfectly. So you cannot share one load cell with two systems. Only the system driving the load cell will be accurate.

Regards,
Jostein

 
Posted : 04/11/2016 8:43 pm
Share:
Select your currency
EUR Euro
USD United States (US) dollar